January 13, 2004
14:37
WSPC/101-CEJ
00097
1
z0, m
522
N. C. Kr0.9 s
au
0.1
0.8
1
z0, m
0.7
0.9
011
.
0.6
0.8
2
L = 300 m
0.5
0.7
3
x0 = 10 m
1
0.4
0.6
3
QS = 500 m /day
2
0.3
L = 300 m 3
0.5
QB = 1,000 m /day
3
x0 = 10 m
ze = 5 m; xe = 300 m
0.2
0.4
3
QS = 500 m /day
0.1
0.3
3
QB = 1,000 m /day
0.00
ze 705 m; xe 00300 m00
=0
8=
2
100
200
300
400
500
600
9
1000
Days after Start of Breach
0.1
0
0
100
200
300
400
500
600
700
800
900
1000
Days after Start of Breach
Fig. 5. Solution of Eq. 4 for breach width, different values of initial breach depth.
Fig. 5. Solution of Eq. 4 for breach width, different values of initial breach depth.
Fig. 5. Solution of Eq. 4 for breach width, different values of initial breach depth.
1
3
0.9
2
0.8
1
1
3
0.7
0.9
2
0.6
0.8
1
0.1
L = 300 m
0.5
0.7
x0 = 10 m
0.4
0.6
3
QS = 500 m /day
z0, m
0.1
0.3
3
QB = 1,000 m /day
L = 300 m
0.5
ze = 5 0 mxe = 300 m
x0 = 1 m;
0.2
0.4
3
QS = 500 m /day
z0, m
0.1
0.3
3
QB = 1,000 m /day
0
ze = 00m; xe8=0 00 m900
75
03
0.20
100
200
300
400
500
600
1000
Days after Start of Breach
0.1
Fig. 6. Solution of Eq. 5 for breach depth, different values of initial breach depth.
0
0
100
200
300
400
500
600
700
800
900
1000
Days after Start of Breach
(Fig. 7)g.G. oSothtiionvolume towbreach uelpbr,iuiffestartvafueteof fiortilalrbreacnidiepth.epth,
Fi . 6r w lu n of Eq. 5 f r ard eqdi ith dm rent s lass r ni a ger i h t al d
but then the curves cross at about 30 days elapsed time. The volume then grows
slightly faster for smaller initial depth because of the larger value of the transport
rate aFigh6. bSolutmnthf n q.n tor brieae.h dep2h, different values of initial breach depth.
t t. e otto io oaE o 5 fhe s d c
t2
22
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